The capacitor bank needs to be fully charged in 1 minute. I calculated the time constant and then the resistance value (67 ohms). This would mean that the current draw from the capacitor bank would be 3.73 A at time = 0. So, the instantaneous power at that time would be 250 V * 3.73 A = 933 W. Is this what the power output of the power supply should be rated?

But as the capacitor bank is charging, the current draw from it decreases exponentially which would change the power output of the power supply. So in this case, would the average power output be the number I should use as the rated power output?

I'm hoping to answer is not 933 W as that would mean I should go with the full-bridge topology which I've read is one of the more complicated to build :ambivalence:

Thanks in advance for any help!