MicrosiM said.
“Wire I gave you is 1.27 mm outer diameter, how come its going to handle 2 Amps?”
litz wire 105/40
40awg = .0031" Dia. x 1000 = 3.1mils
3.1mils x 3.1mils = 9.61CM / 500CM/A = .01922 amps per strand x 105 = 2.0181 amps
“Scroll down this page and see other options
http://www.ebay.com/itm/150547940087...84.m1555.l2649
you have : 660/46 (0.04 mm) Litz Wire, single layer nylon insulation, 1.76 mm diameter.
50/32 (0.20 mm) Litz Wire, double layer nylon insulation, 2.10 mm diameter.”
32AWG litz wire is not even good enough for 20Khz.
litz wire 660/46
46awg = .00157" Dia. x 1000 = 1.57mils
1.57mils x 1.57mils = 2.4649CM
2.4649CM / 500CM/A = .0049298A x 660 strands = 3.25A
There is no wright answer for how much current a wire can carry. It depends on what you design for. For continues operation, the following is general guidelines for transformer design.
350CM/A - Very poor. Transformer runs hot at full load.
500CM/A - Good design.
650CM/A - Very conservative. Transformer stays cool at full load.
For audio you can probably get away with the 350CM/A end. I am mostly concerned with making a general power supply so i use 500CM/A as a starting point.
So in the first example of 105/40 at 500CM/A = 2.02A, lets see what 350CM/A comes out as.
litz wire 105/40
40awg = .0031" Dia. x 1000 = 3.1mils
3.1mils x 3.1mils = 9.61CM / 350CM/A = .02745 amps per strand x 105 = 2.88 amps